25x^2-109x+36=0

Solution for 25x^2-109x+36=0 equation:

25x^2-109x+36=0

a = 25; b = -109; c = +36;
Δ = b2-4ac
Δ = -1092-4·25·36
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8281}=91$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-109)-91}{2*25}=\frac{18}{50}
=9/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-109)+91}{2*25}=\frac{200}{50}
=4
$